Answer to Question #187441 in Mechanical Engineering for randz

Question

5. Ten kilograms of steam at 1.1 MPa has an internal energy of 31,228 kJ. Determine a) its

temperature , b) Total enthalpy.

Answer 1

Specific internal energy of wet steam

u = h – pv

Specific volume of wet steam

v = x.v_g 

Specific enthalpy of wet steam, h = h_f + xh_fg