How can we calculate the internal resistance, voltage out put due to unbalanced condition, current through galvanometer for unbalanced and smallest charge in resistance that can be detected of a wheatstone brigde given that Resistance 1=Resistance 2= varrying Resistance 3=Resistance 4=1000 ohms and a galvanometer can detect as low as 0.1 milliamperes?
the potential distribution in free space is given by
V=p^2 e^(-z)sin(phi)
Calculate the electric field strength at (4,pi/4,-1)