Answer to Question #215137 in Electrical Engineering for Nick

Question

Following electrically operated equipments are running as given below. Calculate the energy bill for the month of March, if the energy charges are Rs 525/- per unit Fluorescent Tube 40 Watt, 8 Hrs/day

Fan- 60 Watt, 10 Hrs/day

Geyser -1000 Watt, I Hr/day

Ac-1500 Watt, 4 Hrs/day

Answer 1

$Energy = Power*time\\$

Energy consumed by Fluorescent Tube 40 W per day $= 8∗40 Wh = 0.32kWh$

Energy consumed by Fan 60 W per day $= 8∗60 Wh = 0.48 kWh$

Energy consumed by Geyser 1000 W $=1000*1=1kWh$

Energy consumed by Ac-1500 W $=1500*4=6kWh$

Total energy consumed= $0.32 + 0.48+1+6= 7.8 kWh$

The energy bill for the month of March $=Rs 5.25/-*7.8kWh=Rs 40.95/-$