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why in digital system most of the gates in logic Zero current pass more increace ? explain it.
The outputs of four registers, A, B, C, D, H, L are connected through 8:1 line
multiplexer to the input of a fifth register, X. Each register is 16 bits long. The
required transfers are dictated by four timing variables, T0 through T3 as follows:
T0 : X←A
T1 : X←B
T2 : X←C

A 12 ohm resistor is connected in parallel with series combinations of resistors of 8 and 16 ohms. If the drop across the 8 ohm resistor os 48 volts, determine the total impressed emf and total current.


Three resistors A,B , and C are connected in series to a 117 volt source . If RA= 64 ohms , and EB = 40 volts when the current is 0.5 amp , calculate the resistors RB and RC


to determine the resistances of the three resistors . A,B, and C the following procedure is followed. Ra and Rb are connected in series and emf 21 volts is impressed for a current of 1 amps, Rb and Rc are next connected in series and emf 27 volts is impressed for the same adjusted current , finally Rc and Ra are connected in series emf of 24 volts is impressed for the same adjusted current . What are the ohmic values of A, B and C?


Suppose 8 bit registers have following contents
X=00001111
Y=10101010
Z= 11011011
W=00110011
What will be the 8 bit values of each register after execution of following sequences of
microoperations ?
X ←
Consider the following register transfer statements for two 4-bit registers R1 and R2.
xT: R1← R1+ R2
x' T: R1 ← R2
Every time that variable T = 1, either the content of R2 is added to the content of Rl if
x = 1, or the content of R2 is transferred to R1 if x = 0. Draw a diagram showing the
hardware implementation of the two statements. Use block diagrams for the two 4-bit
registers, a 4-bit adder, and a quadruple 2-to-1-llne multiplexer that selects the inputs
to R l . In the diagram, show how the control variables x and T select the inputs of the
multiplexer and the load input of register R1.
The 8 bit registers initially have values
A=11110010
B=11111111
C= 10111001
D=11101010
Determine 8 bit values of each register after execution of following sequences of
microoperations
A ←
The outputs of four registers, A, B, C, D, H, L are connected through 8:1 line
multiplexer to the input of a fifth register, X. Each register is 16 bits long. The
required transfers are dictated by four timing variables, T0 through T3 as follows:
T0 : X←A
T1 : X←B
T2 : X←C
T3 : X←D
The timing variables are mutually exclusive, which means that only one variable is
equal to 1 at any given time, while the others are equal to 0. Draw a block diagram
showing the hardware implementation of the register transfers. Include the
connections necessary from the four timing variables to the selection inputs of the
multiplexers and to the load input of register X
1. Design a piezoelectric stage capable of positioning with a 0.1nm resolution over a lum range. Assume that you have a power supply that can generate -10V to +100V and a 16 bit DAC board to control the power supply. You can choose any piezo material and geometry; however, you have to provide a reference (web-page, copy of the spec sheet) for the material of your choice. 16-bit board means that the control voltage minimum step is equal to the total range (110V in this case) divided by 216.
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