Question #232180

Simplify the following boolean expression, using four-variable maps:


AB'C + B'C'D' + BCD + ACD' + A'B'C + A'BC'D


1
Expert's answer
2021-09-06T00:52:00-0400

AB/CD00011110001110111111110111\def\arraystretch{1.5} \begin{array}{c:c:c:c:c} AB/CD & 00 & 01 & 11 & 10\\ \hline 00 &1 & &1&1 \\ \hline 01& &1 &1\\ \hline 11& & &1&1\\ \hline 10&1 & &1&1\\ \hdashline \end{array}

Using the karnaugh map.



The boolean is reduce to

ABD+CD+BD+BCA'BD+CD+B'D'+B'C



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