Answer to Question #232180 in Electrical Engineering for Alock kumar

Question

Simplify the following boolean expression, using four-variable maps:

AB'C + B'C'D' + BCD + ACD' + A'B'C + A'BC'D

Answer 1

$\def\arraystretch{1.5} \begin{array}{c:c:c:c:c} AB/CD & 00 & 01 & 11 & 10\\ \hline 00 &1 & &1&1 \\ \hline 01& &1 &1\\ \hline 11& & &1&1\\ \hline 10&1 & &1&1\\ \hdashline \end{array}$

Using the karnaugh map.

The boolean is reduce to

$A'BD+CD+B'D'+B'C$