Simplify the following boolean expression, using four-variable maps:
AB'C + B'C'D' + BCD + ACD' + A'B'C + A'BC'D
AB/CD00011110001110111111110111\def\arraystretch{1.5} \begin{array}{c:c:c:c:c} AB/CD & 00 & 01 & 11 & 10\\ \hline 00 &1 & &1&1 \\ \hline 01& &1 &1\\ \hline 11& & &1&1\\ \hline 10&1 & &1&1\\ \hdashline \end{array}AB/CD00011110001101111111110111
Using the karnaugh map.
The boolean is reduce to
A′BD+CD+B′D′+B′CA'BD+CD+B'D'+B'CA′BD+CD+B′D′+B′C
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