Question #210116

A monkey Is to demonstrate that she recoginizes colors by tossing one red, one black,and one white ball into boxes of the same respective colors, one ball to a boOx. If themonkey las not leamed the colorS and nerely tosses one ball into each box al random,find the probabilities of the following results:

a. There are no color matches.

b.There i5 exactly one color match.


1
Expert's answer
2021-06-25T15:52:01-0400

Let A1A_1 = Color match in red box

Let A2A_2 = Color match in black box

Let A3A_3 = Color match in white box

Part 1

P(No color match) = 1- P[ Atleast one match]

P(No color match)1P[A1UA2UA3]1-P[A_1UA_2UA_3]

P(No color match)1[P(A1)+P(A2)+P(A3)P(A1nA2)P(A2nA3)P(A1nA3)+P(A1nA2nA3)]1-[P(A_1)+P(A_2)+P(A_3)-P(A_1nA_2)-P(A_2nA_3)-P(A_1nA_3)+P(A_1nA_2nA_3)]

1[13+13+13161616+16]=131-[\frac{1}{3}+\frac{1}{3}+\frac{1}{3}-\frac{1}{6}-\frac{1}{6}-\frac{1}{6}+\frac{1}{6}]=\frac{1}{3}


Part 2

P(exactly one match) = 1- [P(All match)+P(no match)]

P(All match) =P(A1)P(A2/A1)P(A3/A1nA2)=13(12)(1)=16= P(A_1)P(A_2/A_1)P(A_3/A_1nA_2) = \frac{1}{3}(\frac{1}{2})(1)=\frac{1}{6}

Now P(Exactly one match) =11613=12= 1-\frac{1}{6}-\frac{1}{3}=\frac{1}{2}


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