Question #210105



Q9


A student answers a multiple-choice examination question that offers four possible

answers. Suppose the probability that the student knows the answer to the question is

8 and the probability that the student will guess is .2. Assume that if the student

guesses, the probability of selecting the correct answer is .25. If the student correctly

answers a question. what is the probability that the student really knew the correct

answer?


Q 10

The probability distribution for a random variable Y is given in table. Find the mean.

variance, and standard deviation of Y .






1
Expert's answer
2021-06-24T16:46:01-0400

Q9

This is a case of the Bayes theorem

Let B1 denote the event that the student knows the answer

and B2 denote the event that the student guesses the answer

Let A denote the event that the student correctly answer

Given P(B1)=0.8P(B_1)= 0.8

P(B2)=0.2P(B_2)=0.2

P(A/B1)=1P(A/B1)=1

P(A/B2)= 0.25

We have to find P(B1/A)=

                                  =0.81[0.81+0.20.25]\frac{0.8*1}{[0.8*1+0.2*0.25]}

  =0.8[0.8+0.05]=\frac{0.8}{[0.8+ 0.05]}

=0.80.85=\frac{0.8}{0.85}

0.9412

Therefore Required Probability is 0.9412


Q10


Mean,μ=Ʃ[X.P(X)]=1.2Mean, μ = Ʃ[X.P(X)] = 1.2

Variance [Ʃ(X2.P(X))μ2]=(2.21.22)=0.76[Ʃ(X².P(X)) - μ²] = (2.2 - 1.2²)= 0.76

Standard deviation,σ=[Ʃ(X2.P(X))μ2]=(2.21.22)=0.8718Standard \space deviation, σ = \sqrt{[Ʃ(X².P(X)) - μ²]} = \sqrt{(2.2 - 1.2²)} = 0.8718


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