Question #155080

 A single phase overhead transmission line delivers 4000 kW at 11 kV at 0·8 p.f. lagging. If resistance and reactance per conductor are 0·15 Ω and 0·02 Ω respectively, calculate

: (i) percentage regulation

(ii) sending end power factor

(iii) line losses 


Expert's answer

Is = Ir = 454.56(L-36.86)

i)- percentage regulation = (VsVr)Vr×100\frac{(Vs-Vr)}{Vr}\times 100

=(11120110000)110000×100\frac{(11120- 110000)}{110000}\times 100

= 1.09%

ii) cosϕ=Cos(36.860.3465)cos\phi= Cos(36.86- 0.3465)

= 0.80log

iii) line losses = I2RlI^2Rl

= (454.54)2(.30)(454.54)^2(.30)

losses = 61982W



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