Answer to Question #129881 in Electrical Engineering for Md.Mostafijur Rahman

Question #129881
Determine whether the following signals are periodic or non periodic if the signal is periodic find the fundamental period of
1. x (t) = 6cos 5/4 t + 2 cos 9/7 t
2. x (t) = sin√3t +cos √3t
1
Expert's answer
2020-08-20T04:34:13-0400

Consider the function


x(t)=6cos(54t)+2cos (97t).x (t) = 6\text{cos} \bigg(\frac{5}{4}t\bigg) + 2 \text{cos }\bigg(\frac{9}{7} t\bigg).

This function is periodic with a period of 175.9


To avoid ambiguity, consider two functions as a second function:


2.1  x(t)=sin(3t)+cos(3t),2.2  x(t)=sin(3t)+cos(3t).2.1\space\space x(t)=\text{sin}(\sqrt3\cdot t)+\text{cos}(\sqrt3\cdot t),\\ 2.2\space\space x(t)=\text{sin}(\sqrt{3t})+\text{cos}(\sqrt{3t}).

The first one is a periodic function with a period of


T=2π33.63.T=\frac{2\pi}{\sqrt3}\approx3.63.

How did we find it? Simplify the sum of a sine and cosine of the same argument, you get


f(t)=sin(kt)+cos(kt)=2 sin(kt+π4).f(t)=\text{sin}(kt)+\text{cos}(kt)=\sqrt2\text{ sin}\bigg(kt+\frac{\pi}{4}\bigg).

This is a simple sine function that is certainly periodic. The period of a periodic function is


T=2πk.T=\frac{2\pi}{k}.


The function 2.2 is not a periodic function.


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