Determine maximum diameter of hole that can be punched through a plate of 10mm thick,if the punch can withstand a compressive stress of 500mpa and ultimate shear stress of 200mpa
Given data:
t=10mmt=10mmt=10mm
σc=500Mpa\sigma_c=500 Mpaσc=500Mpa
τ=200Mpa\tau=200 Mpaτ=200Mpa
Solution:
as we know that
σc×Ac=τ×As\sigma_c\times A_c = \tau\times A_sσc×Ac=τ×As
σc×π/4D2=τ×πDt\sigma_c\times\pi/4 D^2=\tau\times\pi D tσc×π/4D2=τ×πDt
500/4(D)=200×10500/4 (D)= 200\times 10500/4(D)=200×10
D=16mmD= 16 mmD=16mm
This is the required diameter of the hole
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