Question #266947

In an experiment on a venturi meter installed in a 300 mm diameter pipe, the mercury in the differential U-tube manometer connected to the venturi meter deflects 73 mm when 73 l/s of water is flowing in the pipe. If the diameter of the throat of the venturi is 150 mm, calculate Cd for the venturi


1
Expert's answer
2021-11-19T00:07:28-0500

d1= 0.3m

d2=0.15m

x=0.073m

Q=0.073m^3/sec

To calculate:

Cd=?

a1=π/4(0.3)2=0.0706m2 ,a2π/4(0.15)2=0.0176m2a_1=\pi /4 (0.3)^2=0.0706m^2 \space ,a_2 \pi /4 (0.15)^2=0.0176m^2

h=x(Sg/Sw1)=0.073(13.6/11)=0.9198h=x(S_g/S_w-1)=0.073(13.6/1 -1)=0.9198


Q=Cda1a2(2gh)1/2(a12a22)1/2Q=C_d \frac{a_1 a_2(2gh)^{1/2}}{(a_1^2-a_2^2)^{1/2}}


Cd=0.0730.0773C_d=\frac{0.073}{0.0773}


Cd=0.943 coeficiant of dischargeC_d=0.943 \space \text{coeficiant of discharge}


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