Answer to Question #251504 in Civil and Environmental Engineering for Sysy

Question #251504
Compute the passing sight distance for the following data:
Speed of the passing vehicle = 26.67 m/sec
Speed of the overtaken vehicle = 24.44 m/sec
Time of initial maneuver = 4.3 sec
Average acceleration = 1.473 mph/sec
Time of passing vehicle occupies the left lane = 10.4 sec
Distance between the passing vehicle at the end of its maneuver and the opposing vehicle = 76 m
1
Expert's answer
2021-10-15T12:42:12-0400

Passing sight distance

"D=d_1+d_2+d_3\\\\\nd_1= v_b*T_1=26.67*4.3=114.681 m\\\\\nd_2=v_b*T_2+ \\frac{1}{2}*a*T_2=24.44*4+ \\frac{1}{2}*1.473*10.4=105.4196m\\\\\nd_3=76 m\\\\\nD=d_1+d_2+d_3=114.681+105.4196+76=296.1006 m\\\\"

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