Question

Compute the minimum passing sight distance for the following data:
Speed of the passing car = 90 kph
Speed of the overtaken vehicle = 80 kph
Time of initial maneuver = 4 sec
Time passing vehicle occupies the left lane = 9 sec
Distance between the passing vehicle at the end of its maneuver and the opposing vehicle = 80 m

Answer 1

Passing sight distance

$D=d_1+d_2+d_3\\ d_1=0.278 v_b*T_1=0.278*90*4=88.08 m\\ d_2=0.278 v_b*T_2+ \frac{1}{2}*a*T_2=0.278*90*4+ \frac{1}{2}*2.5*9=211.41 m\\ d_3=80 m\\ D=d_1+d_2+d_3=88.08+211.41+80=379.49 m\\$