Calculate the size of a rectangular sedimentation tanks to treat a flow of 12,000 m3/d. Adopt an overflow rate of 20 m3/m2-d and detention time of 4 hours. Use two units in parallel. What will be the minimum weir length required if the weir overflow rate is not to exceed 300 m3/m-d? Also check the horizontal velocity.
Q = 12,000 m3/d Take two units
Q = 12,000/2 = 6000 m3/d
Overflow rate (OR) = 20 m3/m2
We know
A= 6000 =300m2
Now take L/W= 2 L= 2W
Therefore 2W2=A
2W2 = 300
W = 12.24 m
L = 24.48 m
Vh= 24.48 4
= 6.12 m/hr
= 6.12 m/hr < 9m/hr (O.K)
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