Question

Determine the horizontal and vertical components of reaction on the member at the pin A, and the normal reaction at the roller B.

Answer 1

Take moment about A.

$\Sigma M =O$

N_Bcos30(6)-N_Bsin30(2)-750(3)=0

5.19N_B-N_B-2250=0

N_B=536.22 lb

equilibrium of forces along x-direction

$W\Sigma Fx=0$

A_x=N_Bsin30

A_x=536.22sin30

A_x=268.11 lb

equilibrium of forces along y-direction

$W\Sigma Fy=0$

A_y+N_BCos(30)-750=0

A_y+536.22Cos(30)-750=0

A_y=285.61 lb