A baseball player hits a ball such that as it leaves the bat, it has speed of 40 meters per second and has an angle of 440. What is the time that the ball reaches the highest point of its flight?
w=ΔθΔtw= \Delta \theta \Delta tw=ΔθΔt
Δθ\Delta \thetaΔθ is the angular rotation
w is the velocity
Δt=time\Delta t = timeΔt=time
40m/s=440oXtt=0.091sec40 m/s = 440^o Xt\\ t = 0.091 sec40m/s=440oXtt=0.091sec
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