Question

A W360 x 122 section is used as a column with an effective length of 10 m. Determine the maximum load that can be carried at an eccentricity of 300 mm. Should the load be placed on the X or Y axis? Assume σ_y = 290 MPa.

Answer 1

$\sigma_y = \frac{P}{A}[\frac{Pe}{E}sec[\frac{L}{2} \sqrt{\frac{P}{EI}}]]$

Substituting $290*10^6 Pa$ for $\sigma_y$;

$15.5*10^{-3}m^2$ for A;

$200*10^7$ for E;

10 m for L;

$365*10^6$ for I ;

0.3 for e;

$2.01*10^{-3}$ for s

$290*10^6 = \frac{P}{15.5*10^{-3}}[\frac{P*0.3}{2.01*10^{-3}}sec[\frac{10}{2} \sqrt{\frac{P}{200*10^7*365*10^3}}]]$

$P= 173.5385 N$

The coat placed in a direction since the section module is more in the y direction.