If the ratio of the greater angle between diagonals of a rectangle to the
smaller angle is 2: 1 and a > b then, the ratio a: b of sides of the rectangle is?
Given "\\varphi=2 (180^0-\\varphi)"
"\\varphi=360^0-2\\varphi"
"3\\varphi=360^0"
"\\varphi=120^0"
"cot 30^0 = \\frac{a}{b} \\implies a:b = \\sqrt{3}: 1"
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