Answer to Question #248624 in Chemical Engineering for Izzy

Question

Brackish water is desalinated by evaporation for irrigation purposes. If the feed water has 1036.74 ppm of salt, and if the product has to contain 0.0032 % salts as illustrated in Fig 1, what fraction of the feed water should bypass the evaporator?

Answer 1

feed water = 800.96 ppm

product water = 0.0034% = 34 ppm

$800.96 ×( 1-x)= 34 × x\\ 800.96- 800.96x = 34x\\ 800.96 = 834.96x\\ x = 800.96/834.96 = 0.959$

part needed to bypass = $1 − 0.959 1=0.041$