Find the volume of the solid obtained by rotating the region bounded by the curves y=cos(x), y=0, x=0, and x=π/2 about the line y=1.
The problem is faulty: it gives you only one boundary of the region and leaves you to guess about the others.
"Volume = 2\u03c0\\int^{2\u03c0}_0 (1-cosx)\\\\\n= 2\u03c0[x-sinx]^{2\u03c0}_0\\\\\n= 2\u03c0(2\u03c0- 0) \\\\\n= 4\u03c0\u00b2"
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