Find the volume of the solid obtained by rotating the region bounded by the curves y=cos(x), y=0, x=0, and x=π/2 about the line y=1.
The problem is faulty: it gives you only one boundary of the region and leaves you to guess about the others.
Volume=2π∫02π(1−cosx)=2π[x−sinx]02π=2π(2π−0)=4π2Volume = 2π\int^{2π}_0 (1-cosx)\\ = 2π[x-sinx]^{2π}_0\\ = 2π(2π- 0) \\ = 4π²Volume=2π∫02π(1−cosx)=2π[x−sinx]02π=2π(2π−0)=4π2
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