Answer to Question #239778 in Chemical Engineering for prince

Question

Domestic LPG cylinder has the following dimensions: height = 580 mm, diameter = 318 mm. Assume there is only butane in the cylinder. Given that the initial pressure inside the cylinder is 2.5 bar and the ambient temperature is 298.15 K. According to the print on the cylinder, a full cylinder has 15 kg gas. Some part of butane is in liquid state and some part is in gas state. Use Redlich Kwong equation of state for all process calculations. (a) Develop the expression for total moles of the gas in terms of volume of cylinder, molar volume of liquid butane, molar volume of gaseous butane, fraction of cylinder volume filled with liquid butane. [2] (b) Convert the above relationship in terms of liquid compressibility factor Zl and gas compressibility factor Zv [2] (c) Use the above relationship to develop the equation for finding the fraction of cylinder volume filled with liquid butane. [2] (d) Estimate Zl [10] (e) Estimate Zv [10] (f) Estimate fraction of cylinder volume filled with liquid butane. [5]

Answer 1

V=2.447m3

Weight of full cylinder=29kg

Weight after usage=23.2kg

Gas consumed=$29−23.2=5.8kg$ or 5800g

For butane$(C4​H10​),M=58$

Normal pressure=1atm

Room temperature=298K

$PV=nRT$

$or V=2446.58L≈2.447m ^3$