A car manufacturer claims that its car can accelerate from rest to 28 m/s in 14 seconds. Find the average acceleration and the distance the car has traveled while in the process of stopping
Average Acceleration
a=Vf−Vita=\frac{V_f-V_i}{t}a=tVf−Vi
=(28−0)/14=2m/s2=(28-0)/14=2m/s^2=(28−0)/14=2m/s2
distance=?
d=std=std=st
d=28m/s×14sd=28m/s \times14sd=28m/s×14s
d=392md=392md=392m
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