Question #239556

A car manufacturer claims that its car can accelerate from rest to 28 m/s in 14 seconds. Find the average acceleration and the distance the car has traveled while in the process of stopping


1
Expert's answer
2021-09-23T03:05:32-0400

Average Acceleration

a=VfVita=\frac{V_f-V_i}{t}


=(280)/14=2m/s2=(28-0)/14=2m/s^2


distance=?


d=std=st

d=28m/s×14sd=28m/s \times14s

d=392md=392m


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