Answer to Question #231018 in Chemical Engineering for Lucky

Question

1)For the reaction A products, the temperature is increased from 300°C to 500°C, and then the times of reaction have been doubled What is the activation energy for the particular reaction? (se Arthenius theory)

Answer 1

The activation energy can be determined using the equation:

ln(k₂/k₁) = E_a/R x (1/T₁ - 1/T₂)

where

E_a = the activation energy of the reaction in J/mol

R = the ideal gas constant = 8.3145 J/K·mol

T₁ and T₂ = absolute temperatures (in Kelvin)

k₁ and k₂ = the reaction rate constants at T₁ and T₂