Answer to Question #231011 in Chemical Engineering for Lucky

Question

At 650°C phosphene vapor decomposes as follows:

APH3 → P4 + 6H₂ -rph (10h-¹)Cph,What size of plug flow reactor operating at 650°C and 11.4atm.is needed for conversion of 10 mole/hr of phosphine in a feed of 75% is phosphane and rest is inert

Answer 1

Given F_A0=10mole/hr, K=10/hr, X_A=.75

Temp = 650^oC=923^oK,

P=11.4atm=11.4×101325=1155105pa

V=F_A0/KC_A0[(1+€_A)ln1/(1-X_A)-€_AX_A]----1

C_A0=P_A0/RT=

1155105pa/8.314pa.(m3/mol.K)(923K)

C_Ao= 150.52mol/m³

Put C_AO in the above (1)

V=10/10×150.52[(1+0.75)ln(1/10.75)- 0.75×0.75]------(2)

On solving the above equation (2)

We get

V=0.01732 m³

Size of plug flow reactor is V = 0.01732m³