TC=3x+xy+4y
P1=60−x+y and P2=40+2x−y
π=xp1+yp2−(3x+xy+4y)
=x(60−x+y)+y(40+2x−y)−(3x+xy+4y)
=60x−x2+xy+40y+2xy−y2−3x−xy−4y
=−x2+2xy+57x−y2+36y
FOC:
Dπ(x,y)=[ΔxΔπΔyΔπ]
=[−2x+2y+572x−2y+36]
Solving simultaneously;
x=5.25 y=2.13
P1=60−5.25+2.13=56.88 and P2=40+2(5.25)−2.13=48.37
Maximum profit;
π=xp1+yp2−(3x+xy+4y)
=5.25(56.88)+2.13(48.37)−3(5.25)+5.25×2.13+4(2.13)=405.6
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