Answer to Question #280951 in Microeconomics for abeni

Question #280951

Suppose that , firm under perfectly competition market produce two commodities X1 and X2 with corresponding prices birr 10 and birr 15 . If cost function of the firm is TC= 2x12 +x1x2+2x22 where x1 and x2 denote the level of output, then, determine the following questions.

i. Profit maximizing level of output x1 and x2

ii. The amount of maximum profit


1
Expert's answer
2021-12-20T10:21:17-0500

Price of X1=P1=10\space X_1 =P_1=10

Price of X2=P2=15X _ 2 ​ =P_ 2 ​ =15

Cost function C=2X12+X1X2+2X22C=2X_1^2+X_1X_2+2X_2^2

Total Revenue R=P1X1+P2X2=10X1+15X2Total\space Revenue\space R=P_1X_1+P_2X_2\\=10X_1+15X_2

Profit π=RC=10X1+15X22X12X1X22X22Profit\space \pi=R-C\\=10X_1+15X_2-2X_1^2-X_1X_2-2X_2^2

To find the profit maximizing output of X1:X_1:

δπδX1=0\frac{\delta \pi}{\delta X_1}=0

    δπδX1(10X1+15X22X12X1X22X22)=0\implies\frac{\delta \pi}{\delta X_1}(10X_1+15X_2-2X_1^2-X_1X_2-2X_2^2)=0

    10+04X1X20=0\implies10+0-4X_1-X_2-0=0

    4X1+X2=10.........................................1\implies4X_1+X_2=10.........................................1


To find the profit maximizing output of X2:X_2:

δπδX2=0\frac{\delta \pi}{\delta X_2}=0

    δπδX2(10X1+15X22X12X1X22X22)=0\implies\frac{\delta \pi}{\delta X_2}(10X_1+15X_2-2X_1^2-X_1X_2-2X_2^2)=0

    0+150X14X2=0\implies0+15-0-X_1-4X_2=0

    X1+4X2=15...........................................2\implies X_1+4X_2=15...........................................2


Eq1×4    16X1+4X2=40Eq2×1    X1    +4X2=15                         15X1            =25X1=2515    X=g53X11 unitEq1\times4\implies16X_1+4X_2=40\\\underline{Eq2\times1\implies X_1\space \space \space \space +4X_2=15}\\\space \space \space \space \space \space\space\space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space 15X_1\space \space \space \space \space \space\space \space \space \space \space \space =25\\X_1=\frac{25}{15}\\\implies X=\frac{g5}{3}\\X_1\approx1\space unit


In Eq

1, 4X1+X2=10    X2=104(53)X2=30203X2=(103)X23 units4X_1+X_2=10\\\implies X_2=10-4(\frac{5}{3})\\X_2=\frac{30-20}{3}\\X_2=(\frac{10}{3})\\X_2\approx3 \space units

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