Question #280951

Suppose that , firm under perfectly competition market produce two commodities X1 and X2 with corresponding prices birr 10 and birr 15 . If cost function of the firm is TC= 2x12 +x1x2+2x22 where x1 and x2 denote the level of output, then, determine the following questions.

i. Profit maximizing level of output x1 and x2

ii. The amount of maximum profit


Expert's answer

Price of X1=P1=10\space X_1 =P_1=10

Price of X2=P2=15X _ 2 ​ =P_ 2 ​ =15

Cost function C=2X12+X1X2+2X22C=2X_1^2+X_1X_2+2X_2^2

Total Revenue R=P1X1+P2X2=10X1+15X2Total\space Revenue\space R=P_1X_1+P_2X_2\\=10X_1+15X_2

Profit π=RC=10X1+15X22X12X1X22X22Profit\space \pi=R-C\\=10X_1+15X_2-2X_1^2-X_1X_2-2X_2^2

To find the profit maximizing output of X1:X_1:

δπδX1=0\frac{\delta \pi}{\delta X_1}=0

    δπδX1(10X1+15X22X12X1X22X22)=0\implies\frac{\delta \pi}{\delta X_1}(10X_1+15X_2-2X_1^2-X_1X_2-2X_2^2)=0

    10+04X1X20=0\implies10+0-4X_1-X_2-0=0

    4X1+X2=10.........................................1\implies4X_1+X_2=10.........................................1


To find the profit maximizing output of X2:X_2:

δπδX2=0\frac{\delta \pi}{\delta X_2}=0

    δπδX2(10X1+15X22X12X1X22X22)=0\implies\frac{\delta \pi}{\delta X_2}(10X_1+15X_2-2X_1^2-X_1X_2-2X_2^2)=0

    0+150X14X2=0\implies0+15-0-X_1-4X_2=0

    X1+4X2=15...........................................2\implies X_1+4X_2=15...........................................2


Eq1×4    16X1+4X2=40Eq2×1    X1    +4X2=15                         15X1            =25X1=2515    X=g53X11 unitEq1\times4\implies16X_1+4X_2=40\\\underline{Eq2\times1\implies X_1\space \space \space \space +4X_2=15}\\\space \space \space \space \space \space\space\space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space 15X_1\space \space \space \space \space \space\space \space \space \space \space \space =25\\X_1=\frac{25}{15}\\\implies X=\frac{g5}{3}\\X_1\approx1\space unit


In Eq

1, 4X1+X2=10    X2=104(53)X2=30203X2=(103)X23 units4X_1+X_2=10\\\implies X_2=10-4(\frac{5}{3})\\X_2=\frac{30-20}{3}\\X_2=(\frac{10}{3})\\X_2\approx3 \space units

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