Question #273817

Do each of a-d, both geometrically (you need not be precise) and using calculus. There are only two goods; x is the quantity of one good and y of the other. Your income is I and u(x,y) = xy + x + y.


(a) Px = $2; Py = $1; I = $15. Suppose Py rises to $2. By how much must I increase in order that you be as well off as before?


(b) In the case described in part (a), assuming that I does not change, what quantities of each good are consumed before and after the price change? How much of each change is a substitution effect? How much is an income effect?


(c) Px = $2; I =$15. Graph the amount of Y you consume as a function of Py , for values of Py ranging from $0 to $10 (your ordinary demand curve for Y).


(d) With both prices equal to $1, show how consumption of each good varies as I changes from $0 to $100.



1
Expert's answer
2021-12-07T12:47:22-0500

Solution

(a)

Maximize:

U(x,y)=xy+x+yU(x,y)=xy+x+y

Subject to I=Pxx+PyyI = P_x x + P_y y

Lagrangian for the problem:

L(x,y,λ)=xy+x+y+λ(IPxxPyy)L(x,y,\lambda) = xy+x+y+λ(I-P_xx-P_yy)

First-order conditions(derivatives):


L/x=y+1λPx=0∂L/∂x=y+1-λ^* P_x=0 (1)


L/y=x+1λPy=0∂L/∂y=x+1-λ^* P_y=0 (2)


L/λ=IPxxPyy=0∂L/∂λ=I-P_x x-P_y y=0 (3)


Using the first two conditions(1 and 2) we have

(y+1)/Px=(x+1)/Py(y+1)/P_x=(x+1)/P_y

So,

y=((Px/Py)(x+1))1y^*=((P_x/P_y)(x+1))-1 ​ (4)


Substitute this into I function

I=Pxx+Py(((Px/Py)(x+1))1)I=P_xx+P_y(((P_x/P_y)(x+1))-1)

I=Pxx+Pxx+PxPyI=P_xx+P_xx+P_x-P_y

I=2Pxx+PxPyI=2P_xx+P_x-P_y (5)

solve for x using (5)

2Pxx=IPx+Py2P_xx=I-P_x+P_y

x=(IPx+Py)/2Pxx^*=(I-P_x+P_y)/2P_x (6)

Substitute x* into (4)


y=((Px/Py)((IPx+Py)/2Px+1))1y^*=((P_x/P_y)((I-P_x+P_y)/2P_x+1))-1 ​


y=(IPy+Px)/2Pyy^*=(I-P_y+P_x)/2P_y



Demand function of Both Goods are:

x=(IPx+Py)/2Pxx^*=(I-P_x+P_y)/2P_x

y=(IPy+Px)/2Pyy^*=(I-P_y+P_x)/2P_y


I= 15, Px=2 and Py=1

Before Increase

x=(152+1)/22=3.5x^*=(15-2+1)/2*2=3.5

y=(151+2)/21=8y^*=(15-1+2)/2*1=8

Initial Utility

U(3.5,8)=3.5(8)+3.5+8=39.540U(3.5,8)=3.5(8)+3.5+8=39.5\to40

To make same utility after Py increased to $2

x=(I+22)/22=I/4x=(I+2-2)/2*2=I/4

y=(I+22)/22=I/4y=(I+2-2)/2*2=I/4

So,

U(2,2)=(I/4)2+I/4+I/4=40U(2,2)=(I/4)^2+I/4+I/4=40

=(I2+8I)/16=40=(I^2+8I)/16=40

I2+8I640I^2+8I-640

Solving for I

I=8±((64+(4640)))/2=(8±51.22)/2=±21.61I=-8± ( √(64+(4*640)))/2=(8±51.22)/2=±21.61


Income is non-negative so it's $21.61

Therefore I should be increased by: 21.6115=21.61-15= $6.61


(b)

After an increase of Py to $2

x=(152+2)/22=3.75x^*=(15-2+2)/2*2=3.75

y=(152+2)/22=3.75y^*=(15-2+2)/2*2=3.75

consumption of X and Y is 3.75 each

Substitution effect:

Y=83.75=4.25Y= 8-3.75= 4.25

X=3.53.75=0.25X=3.5-3.75=-0.25

So more of X will be consumed and amount of Y consumed


(c)

Px = $2; I =$15

Y=(IPy+Px)/2Py=(15Py+2)/22Y=(I-P_y+P_x)/2P_y =(15-P_y+2)/2*2

Y=(17Py)/4Y=(17-P_y)/4


Graph of Y as a function of Py





(d)

Px=Py=P_x=P_y= $1

x=(I1+1)/2(1)=I/2x^*=(I-1+1)/2(1)=I/2

y=(I1+1)/2(1)=I/2y^*=(I-1+1)/2(1)=I/2


Therefore, when Income is at 0 the, demand for both x and y is 0, and as income increases from 0 to 100, their demand tends to increase also.

at 100 demands are:

X=Y=100/2=50X=Y=100/2=50

So, demand for X, and Y become 50 each



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