π1= -Q²+17Q-42 π2 = -Q²+16Q-38, at what level of output will profit be zero?
Given; π1= -Q²+17Q-42 π2 = -Q²+16Q-38
The output will zero when δπδQ=0\frac{\delta\pi}{\delta Q}=0δQδπ=0
For π1= -Q²+17Q-42
δπδQ=−2Q+17\frac{\delta\pi}{\delta Q}=-2Q+17δQδπ=−2Q+17
Q=172=8.5Q=\frac{17}{2}=8.5Q=217=8.5
For π2 = -Q²+16Q-38;
δπδQ=−2Q+16\frac{\delta\pi}{\delta Q}=-2Q+16δQδπ=−2Q+16
Q=162=8.0Q=\frac{16}{2}=8.0Q=216=8.0
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