Question #209418

i. Suppose that the production function for compact disc player is

𝑄=100𝐿0.6𝐾0.4

Where 𝑄 is the total output, 𝐿 is the quantity of labor employed, and 𝐾 is the quantity of capital in place.

a) Calculate TP, AP, and MP for the sixth, seventh and eighth units of labour employed if capital is fixed at 240 units.


1
Expert's answer
2021-06-22T10:19:32-0400

Given 

Q=100L0.6K0.4.......(1)Q= 100L^{0.6}K^{0.4} ....... (1)

Where Q is total output, L is the quantity of labor employed. K is quantity of capital. 

If capital is fixed at K=240K=240

So 

Q=100L0.62400.4Q= 100L^{0.6} 240^{0.4}

Q=895.54L0.6......(2)Q= 895.54 L^{0.6} ...... (2)


Average product of labor, 

Dividing output function by L

AP(L)=895.54L(0.4).......(3)AP(L) = 895.54 L^{(-0.4)} ....... (3)

Marginal product of labor, differentiate equation 2 w r t L

MP(L)=TP(n)TP(n1)..........(4)MP(L) =TP(n)-TP(n-1) .......... (4)

 

When L=6L = 6

Q=895.54(60.6)Q=2624.07Q= 895.54{ (6^{0.6})}\\ Q= 2624.07

So total product is2624.072624.07

Average product 

AP=895.54(6)(0.4)=437.345AP= 895.54 (6)^{(-0.4)}=437.345

Marginal product of laborMP(6)=Q(6)Q(5)=2624.07895.54(50.6)=271.91MP(6) =Q(6)-Q(5) =2624.07-895.54 (5^{0.6}) =271.91


When labor is L= 7 

Total product 

Q=895.54(70.6)Q=2878.35Q= 895.54 (7^{0.6})\\ Q= 2878.35

So total product is 2878.352878.35

Average product 

AP=895.54(7)(0.4)=411.19AP= 895.54 (7)^{(-0.4)}=411.19

Marginal product of labor

MP(7)=TP(7)TP(6)=254.28MP(7) =TP(7)-TP(6) =254.28

When L = 8

Total product 

Q=895.54(80.6)Q=3118.45Q= 895.54 (8^{0.6}) \\ Q= 3118.45

So total product is 3118.453118.45

Average product 

AP=895.54(8)(0.4)=389.81AP= 895.54 (8)^{(-0.4)}=389.81

Marginal product of labor

MP(8)=TP(8)TP(7)=240.1MP(8) =TP(8)-TP(7)= 240.1


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