Q=20−0.5PTC=4Q2−8Q+15
a)
Q=20−0.5P0.5P=20−Q⟹P=0.520−Q
⟹40−2QTR=P×QTR=(40−2Q)Q
MR=dQdTRMR=40−4QandTC=4Q2−8QMC=dQdTC=8Q−8
Equilibrium
MR=MC⟹40−4Q=8Q−8⟹40+8=8Q+4Q⟹12Q=48⟹Q=1248=4
Optimum quantity
Q=4P=40−2(Q)=40−2(4)=40−8P=32
(b)now
TR=P×Q=32×4=128TC=4Q2−8Q+15=4(42)−8(4)+15TC=47profit=TR−TC=128−47=81
c)
TC=4Q2−8Q+15VC=4Q2−8QAVC=QVC=Q4Q2−8QAVC=4Q−8
for P<AVC
⟹40−2Q<4Q+2Q⟹40+8<4Q+2Q⟹48<6Q⟹648<Q⟹8<Q
for Q>8 we have P<AVC
let Q=8
P=40−2QP=40−2(8)P=40−16⟹P=24P<24
firm shut down
d)
ATC=QTC=Q4Q2−8Q+15=4Q−8+Q15ATC=4(4)−8415=11.75
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