QUESTION 1
A firm uses a single input labour to produce output q according to the production
𝑞 = 8√𝐿
The commodity sells for R150 per unit and the wage rtae is R75 per hour.
a) Find the profit maximizing quantity of L (3)
b) Find the profit maximizing quantity of q and the level of maximum profit. (5)
c) Suppose now the firm is taxed at R30 per unit of output and that the wage rate is subsidized
at a rate of R15 per hour. Assume that the firm is a price taker, so the price of the producer
remains at R150. Find the new profit maximizing levels of L, q and profit. (6)
d) Nowsupposethefirmisrequiredtopaya20percenttaxonitsprofits,Findthenewprofit maximizing levels of L, q and profit.
Solution:
a.). The profit maximizing quantity of L: This is where the firm’s marginal revenue product of labor (MRP) equals the wage (W).
"MRP_{L} = W"
"MRP_{L} = MPL\\times P"
"P = Price \\;of\\;the\\;commodity = 150"
"W = 75"
"MPL = \\frac{\\partial Q} {\\partial L} = \\frac{4}{L^{1\/2} }"
"Therefore:"
"MRP_{L} = W"
"(\\frac{4}{L^{1\/2} })\\times 150 = 75"
"\\frac{600}{L^{1\/2} } = 75"
"75L^{1\/2} = 600"
"L^{1\/2} = \\frac{600}{75} =8"
"Square\\; both \\;sides:"
"L = 64"
"The \\;quantity\\; of \\;labor \\;that \\;will \\;maximize\\; profit = 64"
b.). Profit maximizing quantity of q and the level of maximum profit:
"Q = 8\\sqrt{L}"
"Substitute\\; L \\;in\\; the \\;equation:"
"Q = 8\\sqrt{64}"
"Q = 8\\times8 = 64"
"Profit \\;maximizing\\; quantity\\; of\\; q = 64"
"The \\;level\\; of\\; maximum\\; profit = Price\\times Quantity"
"Profit = 150\\times64 = 9,600"
"The\\; level\\; of\\; maximum\\; profit = R9,600"
c.). "MRP_{L} = W"
"MRP_{L} = MPL\\times P"
"P = Price \\;of\\;the\\;commodity = 150"
"W = 75 - 15 = 60"
"MPL = \\frac{\\partial Q} {\\partial L} = \\frac{4}{L^{1\/2} }"
"Therefore:"
"MRP_{L} = W"
"(\\frac{4}{L^{1\/2} })\\times 150 = 60"
"\\frac{600}{L^{1\/2} } = 60"
"60L^{1\/2} = 600"
"L^{1\/2} = \\frac{600}{60} =10"
"Square\\; both \\;sides:"
"L = 100"
"The \\; new\\;quantity\\; of \\;labor \\;that \\;will \\;maximize\\; profit = 100"
To get the new profit maximizing quantity of q and the level of maximum profit:
"Q = 8\\sqrt{L}"
"Substitute\\; L \\;in\\; the \\;equation:"
"Q = 8\\sqrt{100}"
"Q = 8\\times10 = 80"
"Profit \\;maximizing\\; quantity\\; of\\; q = 80"
"The \\;level\\; of\\; maximum\\; profit = Price\\times Quantity"
"Profit = 150\\times80 = 12,000"
"The\\; level\\; of\\; maximum\\; profit = R12,000"
d.). "New\\;price = 150 + (20 \\% \\;tax\\;increase) = 180"
"MRP_{L} = W"
"MRP_{L} = MPL\\times P"
"P = Price \\;of\\;the\\;commodity = 180"
"W = 75 - 15 = 60"
"MPL = \\frac{\\partial Q} {\\partial L} = \\frac{4}{L^{1\/2} }"
"Therefore:"
"MRP_{L} = W"
"(\\frac{4}{L^{1\/2} })\\times 180 = 60"
"\\frac{720}{L^{1\/2} } = 60"
"60L^{1\/2} = 720"
"L^{1\/2} = \\frac{720}{60} =12"
"Square\\; both \\;sides:"
"L = 144"
"The \\; new\\;quantity\\; of \\;labor \\;that \\;will \\;maximize\\; profit = 144"
To get the new profit maximizing quantity of q and the level of maximum profit:
"Q = 8\\sqrt{L}"
"Substitute\\; L \\;in\\; the \\;equation:"
"Q = 8\\sqrt{144}"
"Q = 8\\times12 = 96"
"Profit \\;maximizing\\; quantity\\; of\\; q = 96"
"The \\;level\\; of\\; maximum\\; profit = Price\\times Quantity"
"Profit = 180\\times96 = 17,280"
"The\\; level\\; of\\; maximum\\; profit = R17,280"
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