Given Information
Demand function
Q−90+2P=0
Average cost function
AC=Q2−8Q+57+Q2
Total cost=AC×quantity
=(Q2−8Q+57+Q2)×Q
=Q3−8Q2+57Q+2
Differentiate Total Cost with respect of Quantity
MC=δQδTC
MC=QQ3−8Q2+57Q+2
=3Q2−16Q+57
To calculate Maximization of MC of output we equate Mc with 0
MC = 0
3Q2−16Q+57=0
a = 3
b = -16
c = 57
b2−4ac=(−16)2−4×3×57
=256−684
=−428.
2a−b±√b2−4ac
=2x3−(−16)±√−428
=36.68i
And another value will be -4.68i
Negative output is not possible hence the 36.68 output will be maximize MC.
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