Question #123916

suppose demand and total cost functions for a monopoly firm are given as follow,

demand function- p=800-3Q

Cost function- Tc=60+40Q+Q2

requered;-

1. total revenue function

2.average revenue function

3. average cost function

4.profit maximizing output

5.profit maximizing price

Expert's answer

1) Total revenue function.

=Price(quantity)=Price(quantity)

=(800−3Q)Q=(800-3Q)Q

=800Q−3Q=800Q-3Q2

2) Average revenue function

Average revenue function==

=Total revenueQuantity=\frac{\text{Total revenue}}{{Quantity}}


=800Q−3Q2Q=\frac{800Q-3Q^{2}}{Q}

Average revenue function=800−3Q\text{Average revenue function}=800-3Q

3) Average cost function

Average cost function=\text{Average cost function}=

Total cost functionQuantity\frac{\text{Total cost function}}{\text{Quantity}}

Average cost function=\text{Average cost function}=

60+40Q+Q2Q\frac{60+40Q+Q^2}{Q}

Average cost function\text{Average cost function} ==

60Q+40+Q\frac{60}{Q}+40+Q


4) Profit maximizing output

Profit maximizing output=\text{Profit maximizing output}=

MR=MCMR=MC

MR=∂TR∂QMR=\frac{\text{∂TR}}{\text{∂Q}}

=800Q−3Q2=800Q-3Q^2

=800−6Q=800-6Q

MC=∂TC∂QMC=\frac{∂TC}{∂Q}

=60+40Q+Q2=60+40Q+Q^2

=40+2Q=40+2Q

=MR=MC=MR=MC

=800−6Q=40+2Q=800-6Q=40+2Q

=800−40=2Q+6Q=800-40=2Q+6Q

760=8Q760=8Q

Q=95Q=95

Profit is maximized at Q=95Q=95

5) Profit maximizing price

P=800−3QP=800-3Q

P=800−3(95)P=800-3(95)

P=800−285P=800-285

P=515P=515

Profit maximizing price is\text{Profit maximizing price is} 515515



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