Consider
u(c)=c−0.5ac2c1+b1=y1c2+b2=y2+(1+ω)b1c1+1+ωc2=y1+1+ωy2
Consider
c1+1+ωc2=x
Define
u′(c1)dc1+βu′(c2)dc2=0dc1dc2=β(u′)c2−u′(c1)u(c1>c2)=c1−0.5ac12=1−ac1
Similary (1−ac2)
Consider c1=c2
c(1−a)c(1−a)=1
However
dc1dc2=βc1−c2=β1
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