Consider
u(c)=cβ0.5ac2c1β+b1β=y1βc2β+b2β=y2β+(1+Ο)b1βc1β+1+Οc2ββ=y1β+1+Οy2ββ
Consider
c1β+1+Οc2ββ=x
Define
uβ²(c1β)dc1β+Ξ²uβ²(c2β)dc2β=0dc1βdc2ββ=Ξ²(uβ²)c2ββuβ²(c1β)βu(c1β>c2β)=c1ββ0.5ac12β=1βac1β
Similary (1βac2β)
Consider c1β=c2β
c(1βa)c(1βa)β=1
However
dc1βdc2ββ=Ξ²c1ββc2ββ=Ξ²1β
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