a)
"Qs = 0.25P + 10\\\\\n\nQd = -0.5p + 100"
If excess demand , price adjustment "\\frac{\u2202p}{\u2202t} = 0.5(Q^d \u2212 Q^s)"
For Long run equilibrium put
"QD = Qd\\\\\n\n0.25P + 10 = -0.5p + 100\\\\\n\n0.25P + 0.5p = 100 - 10\n\n0.30P = 90\\\\\n\nP = \\frac{90}{0.30}\\\\\n\nP = 300"
Now put P = 300 in any equation to calculate the Equilibrium Quantity
Qs = 0.25P + 10
Qs = 0.25*300 + 10
Qs = 75 + 10
Qs = 80
"Qs = 0.25P + 10\\\\\n\nQs = 0.25\\times300 + 10\\\\\n\nQs = 75 + 10\\\\\n\nQs = 80"
b)
The Given Differentiation is "\\frac{\u2202p}{\u2202t} = 0.5(Q^d \u2212 Q^s)"
"\\frac{\u2202p}{\u2202t} = 0.5(-.5p+100-0.25p-10)"
which can be arranged as
"\\frac{\u2202p}{\u2202t} = 0.5(-.5p+100-0.25p-10)"
"\\frac{\u2202p}{\u2202t} = -0.15p+45" where b=-0.15 and c=45
"p=Ae^{bt}-\\frac{c}{b}" where "A=P(0)+\\frac{c}{b}"
since b=-0.15 and c=45, we have "\\frac{c}{b}=-p^*" (i.e equilibrium price)
"P = (P(0) + P*)e^{bt}+p^*"
"P = (P(0) + 300)e^{0.15t} + 300"
Accordingly as b is < 0 this implies it will increase monotonically
through time, therefore market is Dynamically unstable
c)
"When\\space P(0) = 50, A\\\\\n\nP= (P(0) + 300)_e^{0.15t}\u2212 300\\\\P = (50 + 300)_e^{0.15\\times10} \u2212 300\\\\P = (350)\\times4.4816 \u2212 300\\\\P = 820.422"
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