A. Given that in an economy, , I , MS =300, Mt = 0.4Y, and Mz=125-200r where, Y= income, C= consumption, I= investment, MS= money supply, Mt= transactional-precautionary money demand, Mz= speculative money demand and r= interest rate. Calculate; i. The equilibrium level of income and interest rate in this economy
ii. The level of C, I, Mt, and Mz when the economy is in equilibrium
Solution:
i.). The equilibrium level of income and interest rate in this economy:
Derive the IS and LM equations in order to find out the equilibrium level of income and interest rate in this economy.
First obtain IS equation:
Y = C + I
Y = 102 + 0.7Y + 150 – 100r
Y – 0.7Y = 102 + 150 – 100r
0.3Y = 252 – 100r
Y = 840 – 333r
IS equation: Y = 840 – 333r
Then obtain the LM equation:
Money market equilibrium: Md = Ms
Md = M1 + M2 = Mt + Mz
Md = 0.4Y + 125 – 200r
Ms = 300
Therefore, set Md equal to Ms to derive the LM equation:
Md = Ms
0.4Y + 125 – 200r = 300
0.4Y – 200r = 300 – 125
0.4Y – 200r = 175
0.4Y = 175 + 200r
Y = 438 + 500r
LM equation: Y = 438 + 500r
At equilibrium: IS = LM
840 – 333r = 438 + 500r
840 – 438 = 500r + 333r
402 = 833r
r = 0.483
The equilibrium rate of interest is = 0.483%
Substitute the value of r in the IS equation to derive the equilibrium income:
Y = 840 – 333r
Y = 840 – 333(0.483)
Y = 840 – 161
Y = 679
The equilibrium level of income is = 679
ii.). The level of C, I, Mt, and Mz when the economy is in equilibrium:
The level of C = 102 + 0.7Y = 102 + 0.7(679) = 102 + 475 = 577
The level of I = 150 – 100r = 150 – 100(0.483) = 150 – 48 = 102
The level of Mt = 0.4Y = 0.4(679) = 272
The level of Mz = 125 – 200r = 125 – 200(0.483) = 125 – 97 = 28
Comments
Leave a comment