S o l u t i o n Solution S o l u t i o n g i v e n : Y = C + I + G C = 20 + 0.07 Y I = 12 + 0.1 Y G = 10 given :\\
Y=C+I+G\\
C=20+0.07Y\\
I=12+0.1Y\\
G=10 g i v e n : Y = C + I + G C = 20 + 0.07 Y I = 12 + 0.1 Y G = 10
[A] The model in matrix form is:
Y − C − I = 10 − 0.07 Y + C = 20 − 0.1 Y + I = 12 Y-C-I=10\\
-0.07Y
+C=20\\
-0.1Y+I=12\\ Y − C − I = 10 − 0.07 Y + C = 20 − 0.1 Y + I = 12
( 1 − 1 − 1 − 0.07 1 0 − 0.1 0 1 ) ( Y C I ) = ( 10 20 12 ) \begin{pmatrix}
1&-1 & -1\\
-0.07&1 & 0\\
-0.1&0&1
\end{pmatrix}\begin{pmatrix}
Y \\C\\I
\end{pmatrix}=\begin{pmatrix}
10\\
20\\12
\end{pmatrix} ⎝ ⎛ 1 − 0.07 − 0.1 − 1 1 0 − 1 0 1 ⎠ ⎞ ⎝ ⎛ Y C I ⎠ ⎞ = ⎝ ⎛ 10 20 12 ⎠ ⎞
[B]Using cramer's rule to calculate equilibrium values of Y,C & I:
( 1 − 1 − 1 − 0.07 1 0 − 0.1 0 1 ) ( Y C I ) = ( 10 20 12 ) \begin{pmatrix}
1 & -1&-1 \\
-0.07& 1&0\\
-0.1&0&1
\end{pmatrix}\begin{pmatrix}
Y \\
C\\
I
\end{pmatrix}=\begin{pmatrix}
10 \\
20\\
12
\end{pmatrix} ⎝ ⎛ 1 − 0.07 − 0.1 − 1 1 0 − 1 0 1 ⎠ ⎞ ⎝ ⎛ Y C I ⎠ ⎞ = ⎝ ⎛ 10 20 12 ⎠ ⎞
i]Write down the main matrix and find its determinant to be
:Δ 0 = 0.83 \Delta _0= 0.83 Δ 0 = 0.83
ii]Replace the 1st column of the main matrix with the solution vector and find its determinant to be: Δ 1 = 42 \Delta_1=42 Δ 1 = 42
iii]Replace the 2nd column of the main matrix with the solution vector and find its determinant to be: Δ 2 = 19.54 \Delta_2\ =19.54 Δ 2 = 19.54
iv]Replace the 3rd column of the main matrix with the solution vector and find its determinant to be: Δ 3 = 14.16 \Delta_3=14.16 Δ 3 = 14.16
therefore:
Y = Δ 1 Δ 0 = 42 0.83 = 50.60 C = Δ 2 Δ 0 = 19.54 0.83 = 23.54 I = Δ 3 Δ 0 = 14.16 0.83 = 17.06 Y=\frac{ Δ1 }{ Δ_0} = \frac{42}
{0.83} = 50.60\\C= \frac{\Delta_2}
{ Δ_0} =\frac{ 19.54 }{ 0.83} = 23.54\\I= \frac{Δ_3} { Δ _0}= \frac{14.16 }{ 0.83} = 17.06\\ Y = Δ 0 Δ1 = 0.83 42 = 50.60 C = Δ 0 Δ 2 = 0.83 19.54 = 23.54 I = Δ 0 Δ 3 = 0.83 14.16 = 17.06
[C] income multiplier :
i n c o m e m u l t i p l i e r [ I M ] = Δ G D P e q Δ C e q income \ multiplier[{IM}]=\frac{\Delta GDP_{eq}}{\Delta\ C_{eq}} in co m e m u lt i pl i er [ I M ] = Δ C e q Δ G D P e q
therefore : I M = 50.60 23.54 = 2.15 \ IM=\frac{50.60}{23.54}=2.15 I M = 23.54 50.60 = 2.15
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