Question #194835

Acme Tools manufactures and sells cordless in a market where price (p) and demand (D) are related as follows:

p = $40 + (3,000)/D – (4,800)/D2

 

The fixed cost (CF) is $1000 per month and the variable cost per drill (cv) is $46.

 

a)     How many drills should be produced each month to maximize profits?

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

b)     How much is the maximum profit each month?

 

 


1
Expert's answer
2021-05-20T11:36:34-0400

Given;

P=$40+3,000D4,800D2.................................(i)P = \$40 + \frac{3,000}{D} – \frac{4,800}{D^2}.................................(i)


FC=$1000FC=\$1000 and VC=$46VC=\$46 per drill, TC=$1000+46DTC=\$1000+46D


(a) Number of drills to be produced each month to maximize profits

Profit is maximized at the point where MR=MC

TR=P×DTR=P\times D

=[40+3000D4800D2]×D=[40+\frac{3000}{D}-\frac{4800}{D^2}]\times D


=40D+30004800D=40D+3000-\frac{4800}{D}


MR=40(4800D2)MR=40-(-\frac{4800}{D^2})


=40+4800D2=40+\frac{4800}{D^2}


TC=$1000+46D


MC=46MC=46


Taking MR=MC,

40+4800D2=4640+\frac{4800}{D^2}=46


4800D2=4640\frac{4800}{D^2}=46-40


4800D2=6\frac{4800}{D^2}=6


4800=6D24800=6D^2


800=D2800=D^2


D=28.284328D=28.2843\approx28


(b)

Profit=TRTCProfit=TR-TC

Substituting D in equation (i) we calculate the price as follows:

P=$40+3,000284,800282P = \$40 + \frac{3,000}{28} – \frac{4,800}{28^2}


P=141.02P=141.02


Profit=(P×D)(TC)Profit=(P\times D)-(TC)

=(141.02×28)[1000+46(28)]3,948.562,288=1,660.56=(141.02\times 28)-[1000+46(28)]\\3,948.56-2,288=1,660.56


Therefore the maximum profit per month is $1,660.56


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