We solve by the formula:
P=1000.12(1−1(1+0.03)20)+1000(1+0.12)5P=\frac{100}{0.12}({1-\frac{1}{(1+0.03)^{20}}})+\frac{1000}{(1+0.12)^5}P=0.12100(1−(1+0.03)201)+(1+0.12)51000
P=371.94+567.43=939.37
a)answer
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