Chemistry Answers

For the following reaction, 63.2 grams of barium hydroxide are allowed to react with 41.2 grams of sulfuric acid .What is the maximum amount of barium sulfate that can be formed? What is the FORMULA for the limiting reagent?What amount of the excess reagent remains after the reaction is complete? 

Find the number of moles of 96.4g of magnesium chloride, MgCl2.

How many atoms are in 185 grams of Ni

A cup of coffee contains 95.0 milligrams of caffeine. How many grams

is this?

Si se agrega bicarbonato de sodio adicional a la reacción presentada a continuación

2NaHCO3(s) ➜ Na2CO3(s) + H2O(g) + CO2(g)

¿qué sucederá con la reacción general?

Calculate E° for the following:

a.Iron and water to produce iron(II) hydroxide and hydrogen gas.

b.Pt | S2- | S || NO3- | NO | Pt (basic medium).

c.3SO42-(aq)+12H+(aq)+2A1(s) 3SO2(g)+2A13+(aq)

7. Each element has its __________ set of properties. Some properties are __________ by elements. Other properties are _______________to each element. A _______________ ________________ is a characteristic of a substance that can be directly observed or measured with a tool ___________ changing the identity of the substance.

8. Most elements are _______________. They are located to the _________ of the dark, ______________ line that starts in Group _____ and ends in Group _______.

9. Name 3 properties of metals.

10. Nonmetals are found to the _________ of the stair-step line. Name 4 of their properties. 

11. Metalloids have some characteristics of both _________ and ____________. They are located along the ___________ line near the _________ side of the periodic table in groups 13, 14, 15, and 16. 

They include what 5 elements?

12. A chemical property is a characteristic of a substance that _____________ be ________________ without changing the ____________ of the substance. 

Zn(s) + 2HCI(aq) > ZnCI2(aq) + H2(g)

Calculate the mass of 0.105mol Na₂CO₃.10H₂O

Mass of crucible+lid+Mg= 10.90

Crucible+lid= 10.03

Mass of MgO formed - Mass of crucible= 10.90-10.03= 0.87

Calculate:

Mass of MgO

Amount of Mg in the compound

Mass of O2 in the compound

Amount of oxygen in mole

Simple number ratio to oxygen to Mg

Empirical formula of the compound.