Answer to Question #289573 in General Chemistry for Monic

Question

Calculate the mass of 0.105mol Na₂CO₃.10H₂O

Answer 1

Solution:

The molar mass of Na₂CO₃·10H₂O is 286.14 g/mol

Hence,

Mass of Na₂CO₃·10H₂O = (0.105 mol) × (286.14 g / 1 mol) = 30.045 g

Mass of Na₂CO₃·10H₂O = 30.045 g

Answer: 30.045 g of Na₂CO₃·10H₂O