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Draw the chemical structure for the 5-isopropyl-2-sec-butyl-cyclonon-1-ene.
A 4.00 L rigid vessel (see figure below) holds 2.00 L of pure water. The remaining volume holds N2 at 45.0°C. At this stage the pressure gauge on the vessel reads 85.0 kPa. You then load 13.2 g of Be(NO3)2(s) and 15.4 g of N2H5Cl(s) to the container. The salts dissociate completely and a reaction occurs producing both NO(g) and more N2(g). After the reaction has completed, the temperature increased by 5.00°C, with no change in the liquid volume.
Assume that:
o No gas escaped or entered the vessel during the loading of the reagents.
o The liquid phase is free of any gaseous species.
o The ideal gas law applies.
o The reaction is irreversible with a yield of 88.0%.
i. Show that the balanced reaction in alkaline (basic) medium is given by:
4𝑁𝑂3 − (𝑎q) + 3𝑁2𝐻5 + (𝑎q) → 4𝑁𝑂(𝑔) + 3𝑁2(𝑔) + 7𝐻2𝑂(l) + 𝑂𝐻(𝑎q) −
(Show all balancing steps clearly)
ii. Calculate the number of moles of N2(g) and NO(g) after the reaction.
iii. Calculate the partial pressure of N2(g) and NO(g) in kPa after the reaction
Construct a curve for the titration of 50.00 mL of a 0.1000 M solution of H2SO4 with a 0.2000 M solution of NaOH. For each titration, calculate the pH after the addition of 0.00, 12.50, 20.00, 24.00, 25.00, 37.50, 45.00, 49.00, 50.00, 51.00, and 60.00 mL of NaOH.
A 10.00‐g sample containing an analyte is transferred to a 250‐mL volumetric flask and diluted to volume. When a 10.00 mL aliquot of the resulting solution is diluted to 25.00 mL it gives signal of 0.235 (arbitrary units). A second 10.00‐mL portion of the solution is spiked with 10.00 mL of a 1.00‐ppm standard solution of the analyte and diluted to 25.00 mL. The signal for the spiked sample is 0.502. (a) Calculate the weight percent (%w/w) of analyte in the original sample. (7) (b) What calibration method was used here? Explain your answer.
Chloroform is an internal standard in the determination of the pesticide DDT in a polarographic analysis in which each compound is reduced at an electrode surface. A mixture containing 0.500 mM chloroform and 0.800 mM DDT gave signals of 15.3 µA for chloroform and 10.1 µA for DDT. An unknown solution (10.0 mL) containing DDT was placed in a 100‐mL volumetric flask and 10.2 µL of chloroform (FM 119.39 g/mol, density = 1.484 g/mL) were added. After dilution to the mark with solvent, polarographic signals of 29.4 and 8.7 µA were observed for the chloroform and DDT, respectively. (a) Identify the analyte, the technique and the type of signal used. (3) (b) Find the concentration of DDT in the unknown.
What was the effect of the addition of FeCl3 to the sample solution in the dichromate titration? Explain
Calculate the percentage Fe2+ in the salt based on: a) The dichromate titration. b) The permanganate titration using the colour change end point.
A solution made by dissolving 9.81 g of a nonvolatile nonelectrolyte in 90.0 g of water
boiled at 100.37
oC at 760 mm Hg. What is the approximate molecular weight of the
substance?
Answer the following questions IN YOUR OWN WORDS please dont copy paste
1. Vitamin D, a fat-soluble vitamin, is an important agent in maintaining our bones healthy. Because of its purpose, Vitamin D supplements are taken by people in considerable amounts. Explain why people should only take Vitamin D supplements in regulated amounts and not in large quantities.
2. Patrick boils a 7-Up beverage. What will happen to it? Explain in terms of temperature as a factor affecting the solubility of gases in liquids.
3. Bien bought a bottle of Mountain Dew. He has an upcoming exam and unintentionally shakes the bottle out of nervousness. What will happen when he opens the bottle? Explain why that will happen in terms of Henry's Law.
The vapor pressures of pure toluene and pure benzene at 25°C are 13.5 and 95.2 mmHg, respectively. A solution is prepared in which the mole fractions of toluene and benzene are 0.4 and 0.6, respectively. What are the partial pressures of the benzene and toluene above this solution? What is the total pressure of the solution?
