First, the limiting reactant of the reaction must be determined. For the purpose, number of moles (n) of reactants must be calculated.
According to the reaction:
2Al + 3 H2SO4 --> Al2(SO4)3 + 3H2
n (Al) = 180.3 g / (2 × 27 g/mol) = 3.33 mol
n (H2SO4) = 103.4 g / (3 × 98 g/mol) = 0.35 mol
As sulfuric acid is a limiting reactant, the mass of hydrogen gas is:
m (H2) = 103.4 g × 6 g/mol / 294 g/mol = 2.11 g
Answer: 2.11 g of hydrogen gas.
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