During the inhalation, totally 2×1022 molecules of air enter the lungs. This air contains 9 ppm CO molecules. As 1 ppm = 1/1,000,000 = 10-6, the inhaled air contains 2×1022 × 9×10-6 = 18×1016 molecules of carbon monoxide.
Answer: 18×1016 molecules of CO.
Comments
Leave a comment