Question

1. Dr. Gray had 89.4 grams of nitrogen gas and 230 grams of oxygen gas. Which reactant will limit his production of dinitrogen pentoxide? How many grams of dinitrogen pentoxide will be produced?
2N2 + 5O2 → 2N2O5

Answer 1

Question #73749, Chemistry / Other / Completed

Dr. Gray had 89.4 grams of nitrogen gas and 230 grams of oxygen gas. Which reactant will limit his production of dinitrogen pentoxide? How many grams of dinitrogen pentoxide will be produced?

$$2 \mathrm {N} 2 + 5 \mathrm {O} 2 \rightarrow 2 \mathrm {N} 2 \mathrm {O} 5$$

Solution

x – the mass of O2 theoretically required.

x = 5x31.998 g/mol · 89.4 g / 2x28.014 g/mol = 255.285 g. So we have only 230 g. Oxygen will limit the reaction.

$$y = 2 x 108.01 \, \text{g/mol} \cdot 230 \, \text{g} / 5 x 31.998 \, \text{g/mol} = 310.55 \, \text{g}$$

Answer: Oxygen; 310.55 g.

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