Question #70722
The Half life period for catalytic decomposition of AB3 at 50mm is found to be 4 hours and at 100mm it is 2 hours. the order of reaction is ?
Expert's answer
Half-life period of a reaction of an order n is related to initial concentration by the expression:
t_(1⁄2)∝1/(C_0^(n-1) ).
Thus, given initial concentration 50mm and 100mm and half-life time 4h and 2h, respectively:
〖(t_(1⁄2))〗_1/〖(t_(1⁄2))〗_2 =〖(100)〗^(n-1)/〖(50)〗^(n-1) ;4/2=〖(2)〗^(n-1);n-1=1;n=2.
It is a reaction of 2nd order.
t_(1⁄2)∝1/(C_0^(n-1) ).
Thus, given initial concentration 50mm and 100mm and half-life time 4h and 2h, respectively:
〖(t_(1⁄2))〗_1/〖(t_(1⁄2))〗_2 =〖(100)〗^(n-1)/〖(50)〗^(n-1) ;4/2=〖(2)〗^(n-1);n-1=1;n=2.
It is a reaction of 2nd order.
