Question

A student placed the same chemical amount of SO2(g) and NO2(g) into a 1.0L container. At equilibrium, the concentration of both SO3(g) and NO(g) was 0.30mol/L. What was the initial concentration of SO2(g) and NO2(g)? Kc= 9.5
SO2(g)+NO2(g)--> SO3(g)+NO(g)

Answer 1

#68498 Chemistry, Other

A student placed the same chemical amount of $\mathrm{SO}_{2(g)}$ and $\mathrm{NO}_{2(g)}$ into a 1.0 L container. At equilibrium, the concentration of both $\mathrm{SO}_{3(g)}$ and $\mathrm{NO}_{(g)}$ was 0.30 mol/L. What was the equilibrium concentration of $\mathrm{SO}_{2(g)}$ and $\mathrm{NO}_{2(g)}$ ? Kc= 9.5

$$\mathrm {S O} _ {2 (\mathrm {g})} + \mathrm {N O} _ {2 (\mathrm {g})} - > \mathrm {S O} _ {3 (\mathrm {g})} + \mathrm {N O} _ {(\mathrm {g})}$$

Answer:

$$K _ {e q} = \frac {[ N O ] [ S O _ {3} ]}{[ S O _ {2} ] [ N O _ {2} ]}$$ $$9. 5 = \frac {x ^ {2}}{[ 0 . 3 - x ] [ 0 . 3 - x ]}$$ $$9. 5 = \frac {x ^ {2}}{[ 0 . 3 - x ] [ 0 . 3 - x ]}$$ $$x = 0. 2 3$$

Therefore, equilibrium concentrations will be:

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