Calculate the number of Btu evolved at 25 °C when 80 lb pf ZnCl2 are added to 200 lb of water?
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Expert's answer
2016-04-19T10:21:05-0400
Btu – British thermal unit 1 Btu = 1055.06 J = 1.06 kJ 1 lb = 0.454 kg 80 lb = 36.32 kg 200 lb = 90.8 kg M (ZnCl2) = 136 g/mol M (H2O) = 18 g/mol n (ZnCl2) = 36 320/136 = 267 mol n (H2O) = 90 800/18 = 5 044 mol Enthalpy of dissolution of ZnCl2 at this temperature and at this proportion to water is -66 kJ/mol Therefore the amount of heat emitted is: 66*267 = 17 589 kJ =16 593 Btu
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