Question

MgNH4PO4.6H2O loses H2O stepwise as it is heated. Between 40°C and 60°C the monohydrate (MgNH4PO4.H2O) is formed and above 100°C the anhydrous material (MgNH4PO4) is formed. What are the phosphorus percentages of the monohydrate and anhydrous material?

Answer 1

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Answer on Question #48899, Chemistry, Other

Task:

$\mathrm{MgNH_4PO_4.6H_2O}$ loses $\mathrm{H_2O}$ stepwise as it is heated. Between $40^{\circ}\mathrm{C}$ and $60^{\circ}\mathrm{C}$ the monohydrate $(\mathrm{MgNH_4PO_4.H_2O})$ is formed and above $100^{\circ}\mathrm{C}$ the anhydrous material $(\mathrm{MgNH_4PO_4})$ is formed. What are the phosphorus percentages of the monohydrate and anhydrous material?

Answer:

$$M \left(MgNH_4PO_4 \cdot H_2O\right) = 155,3\ \mathrm{g/mol}$$ $$M \left(MgNH_4PO_4\right) = 137,3\ \mathrm{g/mol}$$ $$M(P) = 31\ \mathrm{g/mol}$$ $$\% P \left(MgNH_4PO_4 \cdot H_2O\right) = \frac{31}{155,3} \times 100 = 20\%$$ $$\% P \left(MgNH_4PO_4\right) = \frac{31}{137,3} \times 100 = 22,6\%$$