Question

A NaOH solution is standardized by titration with 0.835 g KHP (monoprotic standard acid, MW = 204.2 g/mol). 23.47 mL of the unknown NaOH solution is needed to titrate the 0.835 g KHP to the endpoint. Calculate the concentration of the NaOH solution.

Answer 1

Question #48868, Chemistry, Other

A NaOH solution is standardized by titration with 0.835 g KHP (monoprotic standard acid, MW = 204.2 g/mol). 23.47 mL of the unknown NaOH solution is needed to titrate the 0.835 g KHP to the endpoint. Calculate the concentration of the NaOH solution.

Answer:

$V_{NaOH} = 23.47 \text{ mL}$

$m_{KHP} = 0.834 \text{ g}$

$M_{KHP} = 204.2 \text{ g/mol}$

$$n_{NaOH} = n_{KHP}$$ $$n = c \cdot V$$ $$n = m / M$$ $$c_{NaOH} \cdot V_{NaOH} = m_{KHP} / M_{KHP}$$ $$c_{NaOH} = m_{KHP} / (M_{KHP} \cdot V_{NaOH})$$ $$c_{NaOH} = 0.834 / (204.2 \times 0.02347) = 0.1740 \text{ mol/L}$$

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